中文大写数字转阿拉伯数字(GOLANG)

package main

import (
	"fmt"
	"math"
)

func main() {
	fmt.Println(ConvertChNumberToArNumber("贰拾捌万玖仟伍佰肆拾陆元伍角贰分"))
	fmt.Println(ConvertChNumberToArNumber("叁万捌千伍佰叁拾陆元贰角"))
	fmt.Println(ConvertChNumberToArNumber("柒仟叁佰玖拾捌圆整"))
	fmt.Println(ConvertChNumberToArNumber("玖亿捌仟肆佰零陆万叁仟贰佰伍拾柒元捌角肆分"))

}

type chNumberLevel struct {
	Val     float64
	IsPower bool
}

var chPowerNumMap = map[string]*chNumberLevel{
	"亿": {Val: math.Pow10(8), IsPower: true},
	"万": {Val: math.Pow10(4), IsPower: true},
	"仟": {Val: math.Pow10(3), IsPower: false},
	"佰": {Val: math.Pow10(2), IsPower: false},
	"拾": {Val: math.Pow10(1), IsPower: false},
	"千": {Val: math.Pow10(3), IsPower: false},
	"百": {Val: math.Pow10(2), IsPower: false},
	"十": {Val: math.Pow10(1), IsPower: false},
	"元": {Val: math.Pow10(0), IsPower: false},
	"圆": {Val: math.Pow10(0), IsPower: false},
	"角": {Val: math.Pow10(-1), IsPower: false},
	"分": {Val: math.Pow10(-2), IsPower: false},
}

var ChToArNumberMap = map[string]float64{"零": 0, "壹": 1, "贰": 2, "叁": 3, "肆": 4, "伍": 5, "陆": 6, "柒": 7, "捌": 8, "玖": 9}

// ConvertChNumberToArNumber 中文数字转阿拉伯数字
func ConvertChNumberToArNumber(inputStrNum string) (num float64) {
	chNum := []rune(inputStrNum)

	var curNumber float64 //当前数字
	var sumNumber float64 //当前数字*单位权重的值

	for index := 0; index < len(chNum); index++ {
		// 将中文转为阿拉伯数字
		var number = ChToArNumberMap[string(chNum[index])]
		if number > 0 {
			//number > 0表示当前为数字
			curNumber = number
		} else {
			// number 等于 -1 或 0 表示当前为单位,需要计算对应的权重

			//获取对应位的权重和是否大权位
			var powerNum float64
			var isPower bool
			if valM, ok := chPowerNumMap[string(chNum[index])]; ok {
				powerNum, isPower = valM.Val, valM.IsPower
			}

			// 如果是大权位，需要将当前值加起来然后乘以权重
			if isPower {
				sumNumber = (sumNumber + curNumber) * powerNum
				num += sumNumber
				sumNumber = 0
			} else {
				// 如果是小权位，则将当前数字添加到sumNumber中
				if curNumber != 0 {
					sumNumber += curNumber * powerNum
				} else {
					sumNumber += powerNum
				}
			}

			// 最后一次循环时将小权位值的和加入最后的数字中
			if index == len(chNum)-1 {
				num += sumNumber
				break
			}

			//重置当前值为0
			curNumber = 0
		}
	}
	return
}